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Post by brucew268 on Dec 7, 2021 14:17:28 GMT
I should know this but my brain is having a block:
If every circuit is defined by a send and a return, a 'loop' if you will, then how much do upstream components 'do' when the downstream component is turned off? For example, if a preamp has new capacitors that need to be run in, does it do anything if playing music into the preamp but with the power amp turned off? That is just from a 'loop' perspective and doesn't address the question of 'load.
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Post by antonio on Dec 7, 2021 14:44:32 GMT
Is this for 'running in' new equipment Bruce?
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Post by firebottle on Dec 7, 2021 15:41:35 GMT
A circuit usually has an input and an output, not a 'loop'.
There is only a loop to a circuit if there is some form of feedback (usually negative but not exclusively).
There may be feedback built into a preamp or power amp but if they are separate boxes there won't be a loop involved. So burning in caps in a preamp only needs the preamp to be powered.
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Post by brucew268 on Dec 7, 2021 19:06:47 GMT
I was using AndrewT* of diyAudio's language of flow & return in all circuit wires and in thinking of the circuit topology itself. I'm sorry if the term 'loop' threw you off. He mentioned this idea often but only occasionally laid out his full thinking on it, and I can't find one of those full occasions at the moment but here is one mention. One logical extenion of his concept is that all connected boxes become part of an extended circuit due to their cables and often their shared 'common'.
My guess was that having downstream boxes turned on will increase the burn-in effect due to the load on the circuit, but having them off will not do away with it altogether.
*sadly passed away in the last few years, R.I.P.
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Post by firebottle on Dec 8, 2021 16:32:35 GMT
I think in most cases the load of a downstream device is going to be the same whether it is on or off.
BtW There are no stupid questions, only (some) stupid answers.
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